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What is the logarithmic form of the equation e2x ≈ 1732? The logarithmic form of the equation e2x ≈ 1732 is loge1732 = 2x.

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What is the logarithmic form of the equation e3x ≈ 3247? log3x3247 = e ln 3247 = 3x 3 logxe = 3247 ln 3x = 3247 2 See answers Advertisement Advertisement To find : The logarithmic

Get Startede2x = 1732 e 2 x = 1732 Convert the exponential equation to a logarithmic equation using the logarithm base (e) ( e) of the right side (1732) ( 1732) equals the exponent (2x) ( 2 x).

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