\log _2(x+1)=\log _3(27) \ln (x+2)-\ln (x+1)=1 \ln (x)+\ln (x-1)=\ln (3x+12) 4+\log _3(7x)=10 \ln (10)-\ln (7-x)=\ln (x) \log _2(x^2-6x)=3+\log _2(1-x)
To solve this type of equations, here are the steps: Simplify the logarithmic equations by applying the appropriate laws of logarithms. Rewrite the logarithmic equation in exponential form. Now
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