Cos2theta value is I.e, cox2x=cos (x+x) The formula for cos (a+b) is cosa.cosb-sina.sinb Here ,a=x & , b=x Then , put the value,s of a&b We have Cos2x= cosx.cosx- sinx.sinx. Cos2x= cos²x- sin²x . Here we know that sin²x = 1- cos²x

Calculus. Find the Integral cos (theta)^2. cos2 (θ) cos 2 ( θ) Use the half - angle formula to rewrite cos2(θ) cos 2 ( θ) as 1+cos(2θ) 2 1 + cos ( 2 θ) 2. ∫ 1+cos(2θ) 2 dθ ∫ 1 + cos ( 2 θ) 2 d θ. Since 1

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