Point-Slope Equation of a Line
Find the point on the plane x − y + z = 8 that is closest to the point (1, 3, 6). This what I have so far Z = 8-x+y d = Sqrt ((x-1) 2 + (y-3) 2 + (z-6) 2) f(x,y,z) = d 2 = (x-1) 2 + (y-3) 2 +
Find the distance between the 2 points using the distance formula d = ( x 2 − x 1) 2 + ( y 2 − y 1) 2 Insert your points (13, 2) and (7, 10) into the distance equation d = ( 7 − 13) 2 + ( 10 − 2) 2
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