The eleventh-degree polynomial (x + 3) 4 (x − 2) 7 has the same zeroes as did the quadratic, but in this case, the x = −3 solution has multiplicity 4 because the factor (x + 3) occurs four times
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Find the zeros and their multiplicities for the polynomial {eq}p (x) = x^3 (x-3)^2 (x+6) (2x+1)^4 {/eq} Step 1: Find each zero by setting each factor equal to zero and solving the
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The number of times a given factor appears in the factored form of the equation of a polynomial is called the multiplicity. The zero associated with this factor, x= 2 x = 2, has multiplicity 2
How do you find the zeros and how many times do they occur. This video has several examples on the topic. For more math shorts go to www.MathByFives.com
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