In this blog post, we will show you how to Find the point of intersection of the line and the plane.
Putting these values together, we can say the point of intersection of the line and the plane is the coordinate point???\left(\frac35,0,\frac95\right)??? If we want to double
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We can see that $\vec{v}$ is not parallel to any of the coordinate planes thus it is safe to assume that line (1) intersects the plane $y=0$. Plug this into the equation of the 2
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Point of intersection: $P(1-t,3+t,7+2t)$. This point is on the plane, thus: $1-t+2(3+t)+7+2t=20\to 3t+14=20 \to t = 2 \to P=(-1,5,11)$ The normal line to the plane is $N =
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